Kenshin Kodama vs Ryoma Shishimoto
Kenshin Kodama is 0-1-0; Ryoma Shishimoto is 4-1-0. Ryoma Shishimoto is 5 years older than Kenshin Kodama. They have met once: Kenshin Kodama 0, Ryoma Shishimoto 1.
Sig. strikes by zone
Where each fighter lands, as a share of significant strikes
Time in position
Share of fight time at distance, in the clinch and on the ground
How good, really
Each stat against every UFC fighter, in plain words
Ranked against 1483 UFC fighters with five or more UFC fights.
Striking & grappling
Same scale left and right on every row
Bars in a row share one scale. The stronger side is solid; the pale tail behind takedowns is attempts.
Where the strikes land
Range × target
The range × target cross-tab is logged for UFC fights only.
The range × target cross-tab is logged for UFC fights only.
Share of significant strikes landed by range and target · landed / attempted in each cell.
When it ends
Every early finish of their careers, placed at the minute it ended
Recent form · last 5
- L
- WKenshin KodamaRIZIN 53 · May 10, 2026Submission · R1 · 1:11 · 137 lb Catchweight
- WRIZIN Shiwasu no Cho Tsuwamono Matsuri · Dec 31, 2025Submission · R1 · 0:25 · Bantamweight
- WShota IguchiGLADIATOR x DEMOLITION · Jun 3, 2018TKO · R2 · 0:01 · Bantamweight
- WYuki UedaGLADIATOR 005 in Osaka · Jan 21, 2018TKO · R1 · 1:07 · Bantamweight
Head-to-Head History
Frequently asked questions
Have Kenshin Kodama and Ryoma Shishimoto ever fought?
Yes, once. Most recently at RIZIN 53 (Sun, May 10, 2026), where Ryoma Shishimoto won by Submission.
What are the records of Kenshin Kodama and Ryoma Shishimoto?
Kenshin Kodama is 0-1-0 and Ryoma Shishimoto is 4-1-0.
Who is taller, Kenshin Kodama or Ryoma Shishimoto?
Neither. Both stand 5'7" · 170 cm.
Who is older, Kenshin Kodama or Ryoma Shishimoto?
Ryoma Shishimoto is 29 and Kenshin Kodama is 24.
Who has more finishes, Kenshin Kodama or Ryoma Shishimoto?
Kenshin Kodama has 0 wins inside the distance (0 by KO/TKO, 0 by submission); Ryoma Shishimoto has 4 wins (2 by KO/TKO, 2 by submission).

